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In E.Coli DNA, the AT/GC ratio is 0-93. If the number of moles of adenine in the DNA sample is 465,000, calculate the number of moles of guanine present. |
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Answer» Solution :Since the number of MOLES of adenine MUST be equal to that of thymine, therefore , `(A+T)=465,000+465,000=930,000`. Since `(A+T)//(C+G)=0.93`, therefore, number of moles of `C+G=(930,000)/(0.93)=10,00,000` Further since the number of moles of C=number of MOLECULE of G. `therefore` No. of moles of GUANINE (G)`=1000,000//2=500,000`. |
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