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In each of the following pairs of organic compounds, identify the compound which will undergo S_(N^(1)) reaction. Faster. . |
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Answer» Solution :In `S_(N^(1))` reaction, a carbocation intermediate is formed in slow step and the reaction rate depends UPON the stability of the carbocation formed as a RESULT of ionisation. (a). Tert-butly chloride upon ionisation will form a TERTIARY carbocation which is more stab le than the sec-butyl carbocation which will be formed upon the ionisation of secondary butyl chloride.  Tert-butly chloride is more reactive in this case. (b). Benzyl chloride is more reactive towards `S_(N^(1))` reaction than chlorobenzene because it readily ionises to give benzyl carbocation which is RESONANCE stabilized.  In chlorobenzene, ionisation leading to carbocation is not possible. THEREFORE, it is less reactive. |
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