1.

In equimolar solution of glucose, NaCl and BaCl_(2) , the order of osmotic pressure at same temperature is as follow :

Answer»

Glucose `gt NaCl gt BaCl_(2)`
`NaCl gt BaCl_(2)gt` Glucose
`BaCl_(2)gt NaCl gt` Glucose
Glucose `gt BaCl_(2)gt NaCl`

SOLUTION :`BaCl_(2)rArr BA^(2+)+2Cl^(-)=3` ion
`NaCl rArr Na^(+)+CL^(-)=2` ion
Glucose `rArr` No ionisation
`therefore BaCl_(2)gt NaCl gt` Glucose


Discussion

No Comment Found

Related InterviewSolutions