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In example 9 if B is the mid point of rod then find e_(OB)le_(BA) |
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Answer» SOLUTION :`e_(OB)= (1)/(2)B omega((l^(2))/(4))= B omega l^(2)` `e_(BA)=(1)/(2)B omega(x^(2))_((l)/(2))^(l)= (1)/(2)B omega xx(3L^(2))/(4)= (3)/(8)B omega l^(2)` `therefore (e_(OB))/(e_(BA))= (1)/(3)` |
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