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In example 9, if B is the mid point of rod, then find e_(OB)//e_(BA). |
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Answer» SOLUTION :`e_(OB)=(1)/(2)Bomega((l^(2))/(4))=(Bomegal^(2))/(8)` `e_(BA)=(1)/(2)Bomega(x^(2))_(1//2)^(l)=(1)/(2)Bomegaxx(3l^(2))/(4)Bomegal^(2)` `THEREFORE""(e_(OB))/(e_(BA))=(1)/(3)` |
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