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In Example 99, the conditional probability that `X ge 6 " given " X gt 3` equalsA. `(125)/(216)`B. `(25)/(216)`C. `(5)/(36)`D. `(25)/(36)` |
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Answer» Correct Answer - D Let A and B denote the events defined below : A=Getting a six in `6^(th)` or more trial. B=Getting a six in `4^(th)` or more trial. Required probability `=P(A//B)=(P(AcapB))/(P(B))` `implies` Required probability `=(P(X ge 6))/(P(X gt 3))=(((5)/(6))^(5)xx1)/((5)/(6))^(3)=(25)/(36)` |
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