1.

In Example 99, the conditional probability that `X ge 6 " given " X gt 3` equalsA. `(125)/(216)`B. `(25)/(216)`C. `(5)/(36)`D. `(25)/(36)`

Answer» Correct Answer - D
Let A and B denote the events defined below :
A=Getting a six in `6^(th)` or more trial.
B=Getting a six in `4^(th)` or more trial.
Required probability `=P(A//B)=(P(AcapB))/(P(B))`
`implies` Required probability `=(P(X ge 6))/(P(X gt 3))=(((5)/(6))^(5)xx1)/((5)/(6))^(3)=(25)/(36)`


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