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| 1. |
In Exercise. 11 obtain the frequency of revolution of the electron in tis circular orbit. Does the answer depend on the speed of the electron ? Explain . |
| Answer» Solution :Frequency in Exercise 11. `UPSILON = (qB)/(2pim) = (1.6 XX 10^(-19)xx6.5 xx 10^(-4))/(2 xx pi xx 9.1 xx 10^(-31))=18 MHz` | |