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In Exercises 3 and 4, what is the net power absorbed by each circuit over a complete cycle. Explain your answer. |
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Answer» Solution :In EXERCISE 3 Average power `P = V_("rms")` `I_("rms").cos phi` As we KNOW that the PHASE DIFFERENCE between current and voltage in case of inductor is `90^(@)`. `P = V_("rms").I_("rms").cos 90^(@)=0` In Exercise 4 Average power `P = V_("rms").I_("rms").cos phi` We know that the phase difference between current and voltage in case of capacitor is `90^(@)` `P=V_("rms").I_("rms").COS90^(@)=0` |
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