In Fig. 10.64, BC is a tangent to the circle with centre O.OE bisects – InterviewSolution

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1.	In Fig. 10.64, BC is a tangent to the circle with centre O.OE bisects AP. Prove that `Delta ABC ~ Delta AEO`
Answer» `/_AEO and /_PEO` OE=OE(same) CP=EA(given) OA=OD(radius) `/_AEo cong /_PEO` `/_AEO=/_PEO=90^0` `/_AEO and /_ABC` `/_A=/_A`(common) `/_AED=/_ABC=90^0` `/_AEO cong /_ABC (A A similarity)`

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