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In Fig. 5-26a, a constant horizontal force vec(F)_("app") of magnitude 20 N is applied to block A of mass m_(A)=4.0 kg, which pushes against block B of mass m_(B)=6.0 kg. The blocks slide over a frictionless surface, along an x axis. (a) What is the acceleration of the blocks ? |
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Answer» Solution :We can relate not force on block B to the block.s ACCELERATION with Newton.s SECOND law. Calculation: Here we can write that law, still for COMPONENTS along the x axis, as `F_(BA)=M_(B)alpha`, which, with known VALUES, gives `F_(BA)=(6.0" kg")(2.0" m"//"s"^(2))=12" N"`. Thus, force `vec(F)_("BA")` is in the positive direction of the x axis and has a magnitude of 12 N. |
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