In Fig. 9.13, ABCD is a parallelogram and EFCD is a rectangle.Also, `A – InterviewSolution

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1.	In Fig. 9.13, ABCD is a parallelogram and EFCD is a rectangle.Also, `A L_\|_D C`. Prove that(i) `a r (A B C D) = a r (E F C D)`(ii) `a r (A B C D) = D C xx A L`
Answer» As per the given figure, both `ABCD` and `EFCD` lies on the same parallel line `EB` and have common base `CD`. We know, if two parallelograms lie on the same parallel line and have a common base, then they have equal area. Thus, `ar(ABCD) = ar(EFCD)` Also, we can say that ,`ar(ABCD) = ar(EFCD) = DCxxDE` As, `AL` is a perpendicular to `CD` in rectangle `EFCD`, `AL=DE` So, `ar(ABCD) =DCxxAL`

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