InterviewSolution
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InterviewSolution
| 1. |
In Fig., a nonconducting rod of length L = 8.15 cm has a charge -q = -4.23 fC uniformly distributed along its length. (a) What is the linear charge density of the rod ? What are the (b) magnitude and (c ) direction (relative to the positive direction of the x axis) of the electric field produced at point P, at distance a = 6.00 cm from the rod ? What is the electric field magnitude produced at distance a = 50 m by (d) the rod and (e) a particle of charge -q = -4.23 fC that we use to replace the rod ? (At that distance, the rod "looks" like a particle.) |
| Answer» Solution :(a) `-5.19 xx 10^(-14) C//m`, (B) `4.48 xx 10^(-3) N//C`, (c ) `-180^(@)` (d) `1.52 xx10^(-8) N//C`, (E) `1.52 xx 10^(-8) N//C` | |