In fig a sphere of mass 2 kg is suspended from the ceiling of a car which is initially at rest. Tension in the string in this situation is `T_(1)` The car now moves to the right with a uniform acceleration and the tension in the string is now `T_(2)` then: (Take `g=10m//s^(2)`) A. `T_(1)=T_(2)=20N`B. `T_(1)=20N, T_(2) gt20N`C. `T_(1)=20N, T_(2) lt20N`D. `T_(1) lt20N,T_(2)=20N`

In fig a sphere of mass 2 kg is suspended from the ceiling of a car wh

1.	In fig a sphere of mass 2 kg is suspended from the ceiling of a car which is initially at rest. Tension in the string in this situation is `T_(1)` The car now moves to the right with a uniform acceleration and the tension in the string is now `T_(2)` then: (Take `g=10m//s^(2)`) A. `T_(1)=T_(2)=20N`B. `T_(1)=20N, T_(2) gt20N`C. `T_(1)=20N, T_(2) lt20N`D. `T_(1) lt20N,T_(2)=20N`
Answer» Correct Answer - B `T_(1)=mg=2xx10=20N` `T_(2)=sqrt((mg)^(2)+(ma)^(2))=msqrt(g^(2)+a^(2))` Thus, `T_(2) gt T_(1)`

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