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In Fig., AB = AC and ∠ACD = 105°, find ∠BAC. |
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Answer» Given, AB = AC ∠ACD = 105° Since, ∠BCD = 180°(Straight angle) ∠BCA + ∠ACD = 180° ∠BCA + 105° = 180° ∠BCA = 75°(i) Now, ΔABC is an isosceles triangle ∠ABC = ∠ACB (Angle opposite to equal sides) From (i), we have ∠ACB = 75° ∠ABC = ∠ACB = 75° Sum of interior angle of triangle = 180° ∠A +∠B +∠C =180° ∠A = 180° - 75° -75° = 30° Therefore, ∠BAC = 30° |
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