In Fig. AB = AC and AD is the bisector of ∠BAC. (i)State three pai

1.	In Fig. AB = AC and AD is the bisector of ∠BAC. (i)State three pairs of equal parts in triangles ADB and ADC. (ii) Is ΔADB ≅ΔADC? Give reasons. (iii)Is ∠B = ∠C? Give reasons.
Answer» ong>Given :- In Fig. AB = AC and AD is the bisector of ∠BAC. To Find :- (i)State three pairs of equal parts in triangles ADB and ADC. (II) Is ΔADB ≅ΔADC ? Give reasons. (iii)Is ∠B = ∠C ? Give reasons. Solution :- (i) The three pairs of equal parts in ∆ADB and ∆ADC are :- → AB = AC (Given.) → ∠BAD = ∠CAD (AD is the bisector of ∠BAC.) → AD = AD (common.) so, → ∆ADB ≅ ∆ADC (By SAS congruence.) therefore, (ii) is correct . now, → ∠B = ∠C (By CPCT.) hence, (iii) also correct . LEARN more :- in triangle ABC SEG DE parallel side BC. If 2 AREA of triangle ADE = area of quadrilateral DBCE find AB : AD show that B... brainly.in/question/15942930 2) In ∆ABC seg MN \|\| side AC, seg MN divides ∆ABC into two parts of equal area. Determine the value of AM / AB brainly.in/question/37634605

In Fig. AB = AC and AD is the bisector of ∠BAC. (i)State three pairs of equal parts in triangles ADB and ADC. (ii) Is ΔADB ≅ΔADC? Give reasons. (iii)Is ∠B = ∠C? Give reasons.

Answer»

ong>Given :- In Fig. AB = AC and AD is the bisector of ∠BAC.

To Find :-

(i)State three pairs of equal parts in triangles ADB and ADC.

(II) Is ΔADB ≅ΔADC ? Give reasons.

(iii)Is ∠B = ∠C ? Give reasons.

Solution :-

(i) The three pairs of equal parts in ∆ADB and ∆ADC are :-

→ AB = AC (Given.)

→ ∠BAD = ∠CAD (AD is the bisector of ∠BAC.)

→ AD = AD (common.)

so,

→ ∆ADB ≅ ∆ADC (By SAS congruence.)

therefore, (ii) is correct .

now,

→ ∠B = ∠C (By CPCT.)

hence, (iii) also correct .

LEARN more :-

in triangle ABC SEG DE parallel side BC. If 2 AREA of triangle ADE = area of quadrilateral DBCE find AB : AD show that B...

2) In ∆ABC seg MN || side AC, seg MN divides ∆ABC into two parts of equal area. Determine the value of AM / AB