1.

In Fig., ABC is an isosceles triangle whose side AC is produced to E. Through C, CD is drawn parallel to BA. The value of x isA. 52°B. 76°C. 156°D. 104°

Answer»

∠B = ∠C (Angles opposite to equal sides are equal)

In ΔABC,

∠A + ∠B+ ∠C = 180°

∠A = 76°

Now,

∠BAC = ∠ACD (Alternate angles)

∠ACD = 76°

Now,

∠ACD + ∠ECD = 180°

x = 180 - 76°

x = 104°



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