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In Fig., ABC is an isosceles triangle whose side AC is produced to E. Through C, CD is drawn parallel to BA. The value of x isA. 52°B. 76°C. 156°D. 104° |
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Answer» ∠B = ∠C (Angles opposite to equal sides are equal) In ΔABC, ∠A + ∠B+ ∠C = 180° ∠A = 76° Now, ∠BAC = ∠ACD (Alternate angles) ∠ACD = 76° Now, ∠ACD + ∠ECD = 180° x = 180 - 76° x = 104° |
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