InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
In Fig. ABCD and PQRC are rectangles and Q is the mid-point of AC. Prove that(i) DP = PC (ii) PR = \(\frac{1}{2}\)AC. |
|
Answer» (i) In ∆ADC, Q is mid point of AC such that PQ || AD ∴ P is mid point of DC = DP = DC (converse of mid point theorem) (ii) Similarly, R is the mid point of BC = PR = \(\frac{1}{2}\) BD PR = \(\frac{1}{2}\) AC ∵ diagonals of rectangle are equal Proved. |
|