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In Fig,ABCD is a parallelogram and E is the mid-point of side BC. If DE and AB when produced meet at F, Prove that,AF = 2AB. |
Answer» Given, In a parallelgram ABCD, E = mid point of side BC AD || BC AD || BE E is mid point of BC So, In ΔDEC and ΔBEF BE = EC .. (E is the mid point) ∠DEC = ∠BEF ∠DCB = ∠FBE (vertically opposite angles) So, ΔDEC ≅ ΔBEF DC = FB = AB + DC = FB + AB = 2AB = AF (proved) |
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