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In Fig (b) , the magnetic needle has magnetic moment 6.7 xx10^(-2) "Am"^2 and moment of inertia I=7.5xx10^(-6)"kgm"^2 . It performs 10 complete oscillations in 6.70s. What is the magnitude of the magnetic field ? |
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Answer» SOLUTION :The TIME period of OSCILLATION is , `T=(6.70)/10=0.67s ""B=(4pi^I)/(mT^2)=(4XX(3.14)^2xx7.5xx10^(-6))/(6.7xx10^(-2)xx(0.67)^2)=0.01T` |
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