1.

In Fig., determine the apparent shift in the position of the coin. Also, find the effective refractive index of the combinatino of the glass and water slab.

Answer» Total apparent shift is
`s=t_(1)(1-(1)/(mu_(1)))+t_(2)(1-(1)/(u_(2)))`
`=8(1-(1)/(4))+4.5(1-((1)/(3))/2)`
`=2+1.5=3.5cm`
The apparent depth of coin from the top is `t=(8+4.5)-3.5=9cm` and, the real depth of the coin is
`t_(1)+t_(2)=8+4.5=12.5`
Therefore, the effective refractive index is
`mu_(eff)=(" Real depth ")/(" Apparent depth ")`
`=(t_(1)+t_(2))/(t)=(12.5)/9`
`=1.39`


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