

InterviewSolution
Saved Bookmarks
1. |
In Fig., determine the apparent shift in the position of the coin. Also, find the effective refractive index of the combinatino of the glass and water slab. |
Answer» Total apparent shift is `s=t_(1)(1-(1)/(mu_(1)))+t_(2)(1-(1)/(u_(2)))` `=8(1-(1)/(4))+4.5(1-((1)/(3))/2)` `=2+1.5=3.5cm` The apparent depth of coin from the top is `t=(8+4.5)-3.5=9cm` and, the real depth of the coin is `t_(1)+t_(2)=8+4.5=12.5` Therefore, the effective refractive index is `mu_(eff)=(" Real depth ")/(" Apparent depth ")` `=(t_(1)+t_(2))/(t)=(12.5)/9` `=1.39` |
|