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In Fig, find the magnetic field at point P. The loop is lying in x-y plane. |
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Answer» Magnetic field due to circular loop, `vecB_1=(mu_0i)/(2a) (120^@)/(360^@) (hatk)=(mu_0i)/(6a)hatk`. Due to straight wire, `vecB_2=(2mu_0i)/(4pia) xx2sin60(-hatk)=(sqrt3)/2 (mu_0i)/(pia)(-hatk)` `:. vecB_(n et)=(sqrt3)/2 (mu_0i)/(pia)(-hatk)+ (mu_0i)/(6a)(hatk)=(mu_0i)/(2pia)(sqrt3-pi/3)(-hatk)` |
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