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In Fig.(i), a lens of focal length 10 cm is shown. It is cut into two parts and placed as shown in Fig.(ii). An object AB of light 1 cm is placed at a distance of 7.5 cm. The height of the image will be |
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Answer» SOLUTION :`1/F=1/(f_1)+1/(f_2)=1/10+1/10` `:. F=5 cm` `1/v-1/-7.5=1/(+5)` `:. V=+15 cm` `m=v/u=(+15)/(-7.5)=-2` `I=mO=(-2)(1CM)` `=-2 cm` |
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