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In Fig., the measure of ∠B’AC’ isA. 50°B. 60°C. 70°D. 80° |
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Answer» In ΔABC and ΔA'B'C', AB = A'B' (Given) ∠B = ∠B'(Given) BC = B'C' (Given) Hence, by S.A.S. theorem, ΔABC ≅ ΔA'B'C' Therefore, By c.p.c.t ∠A = ∠A' 3x = 2x +20 x = 20° Therefore angle A' = 2x +20 = 60° |
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