1.

In Fig., the measure of ∠B’AC’ isA. 50°B. 60°C. 70°D. 80°

Answer»

In ΔABC and ΔA'B'C',

AB = A'B' (Given)

∠B = ∠B'(Given)

BC = B'C' (Given)

Hence, by S.A.S. theorem,

ΔABC ≅ ΔA'B'C'

Therefore,

By c.p.c.t

∠A = ∠A'

3x = 2x +20

x = 20°

Therefore angle A' = 2x +20

= 60°



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