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In Fig., X is a point in the interior of square ABCD. AXYZ is also a square. If DY = 3 cm and AZ = 2 cm, then BY =A. 5 cmB. 6 cmC. 7 cmD. 8 cm |
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Answer» ∠Z = 90° (Angle of square) Therefore, AZD is a right angle triangle, By Pythagoras theorem, AD2 = AZ2 + ZD2 AD2 = 22 + (2+3)2 AD2 = 4 + 25 AD = √29 In ΔAXB, with x as right angle, By Pythagoras theorem, AB2 = AX2 + XB2 XB2 = 29 - 4 XB = 5 BY = XB + XY = 5 + 2 = 7 cm |
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