1.

In Fig., X is a point in the interior of square ABCD. AXYZ is also a square. If DY = 3 cm and AZ = 2 cm, then BY =A. 5 cmB. 6 cmC. 7 cmD. 8 cm

Answer»

∠Z = 90° (Angle of square)

Therefore, AZD is a right angle triangle,

By Pythagoras theorem,

AD2 = AZ2 + ZD2

AD2 = 22 + (2+3)2

AD2 = 4 + 25

AD = √29

In ΔAXB, with x as right angle,

By Pythagoras theorem,

AB2 = AX2 + XB2

XB2 = 29 - 4

XB = 5

BY = XB + XY

= 5 + 2

= 7 cm



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