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In figure 11.35, ABCDE is a regular pentagon. If angle EBD = 36°, find angle 1,2 and 3 |
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Answer» Answer: Step-by-step explanation: As you KNOW that sum of angles A , B,C,D and E = 540 degree there fore each ANGLE A , B,C ,D and E measures = 108 degree Angle A = 108 degree now in triangle ABE , AB=AE ( because it is regular pentagon, all sides are equal) so Triangle ABE is isosceles triangle. Angle ABE = angle AEB (i) now angle A + angle AEB+ angle AEB = 180 104 + 2 angle ABE= 180 (because of (i) ) angle AEB =36 degree (which is angle 2) SIMILARLY angle 3 = 36 degree
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