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In figure 39,AD andCF are respectively perpendicular to sides BC andAB of ABC .if FCD=50 find BAD |
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Answer» e point of intersection of AD and CE as Oangle ECD= 50 ( given)By ANGLE SUM property in triangle OCDangle OCD +angle ADC+angle DOC=18050 + 90 + X = 180140 +X= 180X=40therefore angle DOC= 40and angle EOA =40 ( VERTICALLY oppo angles)So similarly in triangle AOEangle E + angle EOA+angle EAO =18090 + 40 + x= 180130+x = 180X= 50Therefore, angle BAD = 50 |
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