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In figure A, B and C are three points on a circle with centre O such that \angle BOC = 30º and \angle AOB = 60º. If D is a point on the circle other than the arc ABC, find \angle ADC​

Answer»

-step EXPLANATION:Hello! sis à very very Ğood Mõõrning to u..✌This is your answer (^___^)AOC=∠AOB+∠BOC=60∘+30∘=90∘ARC ABC subtends ∠AOC at centre of a circle.And ∠ADC on point Dtherefore∠AOC=2∠ADC     (ANGLE subtended by arc at the centre is double the angle subtended by it at any point on circumference. )90∘=2∠ADC∠ADC=45∘Hope this may HELPS u..



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