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In Figure AB = 36 cm and M is mid-point of AB. Semi-circles are drawn on AB, AM and MB as diameters. A circle with centre C touches all the three circles. Find the area of the shaded region. |
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Answer» Let the radius of the circle be r. and `triangle PCM` is right `triangle` `PC^2=PM^2+MC^2` `(9+r)^2=(9)^2+(16-r)^2` `81+r^218r=81+324+r^2-36r` `54r=324` `r=324/54=6cm` `Area of shaded region = (324pi)/2-81pi+36pi` `=162pi-117pi` Therefore area of the shaded region `=45picm^2` |
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