In figure, ∠BAC=90∘ and segment AD⊥BC. Prove that AD2=BD×DC. [ – InterviewSolution

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In figure, ∠BAC=90∘ and segment AD⊥BC. Prove that AD2=BD×DC. [3 MARKS]

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In figure, $∠ B A C = 90^{\circ}$ and segment $A D ⊥ B C$ . Prove that ${A D}^{2} = B D \times D C$ . [3 MARKS]

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