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In figure, BD and CEy are altitudes of ∆ABC and ∆BD = CE.(i) Write three pairs of equal parts in ∆CBD and ∆BCE.(ii) Is ∆CBD ≅ ∆BCE ? Why and why not?(iii) Is ∠DCB ≅ ∠EBC ? Why and why not? |
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Answer» (i) Three equal parts in ∆CBD and ∆BCE are CB = BC (common) ∠CDB = ∠BEC (each 90°) and BD = CE (given) (ii) From R.H.S. condition of congruency ∆CBD ≅ ∆BCE (iii) Yes, ∠DCB = ∠EBC (∵ corresponding angles of congruent triangles are equal) |
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