InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
In figure `i_(1) = 10 e^(-2t) A, i_(2) = 4 A, v_(C ) = 3 e^(-2t) V` The potential difference across `AB (V_(AB))` is:A. `8 e^(-2t) V`B. `(1)/(2) e^(-3t) V`C. `17 e^(-2t)`D. `16 e^(-2t) V` |
|
Answer» Correct Answer - C `V_(A) = - i_(1)R_(1) + V_(C ) = V_(B), V_(AB) = V_(A) - V_(B) = i_(1) R_(1) - V_(C )` Substitution the value we have, `V_(AB) = (10 e^(2t)) (2) - 3e^(-2t) , V_(AB) = 17 e^(-2t) V` Thus, `V_(AB)` decreases exponentially from `17 V` to 0. |
|