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In (figure). shows two path that may be taken by a gas to go from a state A to state C In the process AB, `400 J` of heat is added to the system and in process Bc, `100 J` of heat is added to the system. The heat absorbed by the system in the process AC will beA. `500 J`B. `460 J`C. `300 J`D. `380 J` |
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Answer» Correct Answer - B In cyclic process ABCA `DeltaU_(cyclic)=0` From first law of thermodybamics `Q_(cyclic)= W_(cyclic)+U_(cyclic)` `:. Q_(cyclic)= W_(cyclic)` `Q_(AB)+Q_(BC)+Q_(CA)=` closed loop area `400+100+Q_(CA)= 1/2(2xx10^(-3))xx4xx10^(4)` `500-Q_(AC)= 40 [:. Q_(CA)= - Q_(AC)]` `Q_(AC)= 460 J` |
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