InterviewSolution
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InterviewSolution
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In forming `(i) N_(2) rarrN_(2)^(o+)` and `O_(2)rarrO_(2)^(o+)` the electrons respectively removed from .A. `(pi^(**)2p_(y) "or " pi^(**) 2p_(x)) " and " (pi^(**)2p_(y)"or" pi^(**)2p_(x))`B. `(pi 2p_(y) "or " pi 2p_(y)) " and " (pi 2p_(y) "or " 2p_(x))`C. `(sigma 2p_(z))` and `(pi^(**)2p_(y))` or `pi^(**)2p_(x)`D. `(pi^(**)2p_(y) "or " pi^(**) 2p_(x)) " and " (pi 2p_(y) " or " pi 2p_(x))` |
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Answer» Correct Answer - C (i) `N_2 to (sigma1s)^(2) (sigma^(**)1s)^(2)(sigma2s)^(2)(sigma^(**)2s)^(2)(pi 2p_x)^(2) (pi 2p_(y))^(2)(sigma2p_(z))^(2)` `N_(2)^(+) to (sigma1s)^(2)(sigma^(**)1s)^(2) (sigma2s)^2(sigma^(**)2s)^(2)(sigma2p_(z))^(1)` (ii) `O_(2) to (sigma1s)^(2)(sigma^(**)1s)^(2)(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(z))^(2)(pi 2p_(x))^(2) (pi 2p_(y))^(2)(pi^(**)2p_(x))^(1)(pi^(**)2p_(y))^(1)` `O_(2)^(+) to (sigma1s)^(2)(sigma^(**)1s)^(2)(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(z))^(2)(pi 2p_(x))^(2)(pi 2p_(y))^(2)(pi^(**)2p_(x))^1` In `N_(2)^(+)` , electron removes from `sigma2p_(z)` becuase in `N_(2),pi2p_(x)` and `pi2p_(y)` have lower energy in comparision to `sigma2p_(z)`. in `O_(2)^(+)` electron removes either from `pi^(**)2p_(y)` or `pi^(**) 2p_x`. |
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