1.

In fourth group, Mn(OH)_2 on heating with PbO_2 and conc. HNO_3 gives purple colour due to the formation of

Answer»

`HMnO_4`
`K_2 MnO_4`
`PbO_2`
`PbMnO_3`

SOLUTION :`MN(OH)_(2) +2 HNO_(3) to Mn(NO_(3))_(2) + 2 H_(2)O 2 Mn (NO_(3))_(2) + 5 PbO_(2) + 6 H NO_(3) to underset("Purple colour")(2 HMnO_(4)) + 5 Pb (NO_(3))_(2) + 2H_(2)O`


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