1.

In Fraunhoffer diffraction, the wavelength incident light perpendicular to slit made double. the distance from the slit to the screen made tripled and if the width of the slit made (3)/(2) times then width of central maximum will be.....

Answer»

THREE times
four times
doubled
half

SOLUTION :In diffraction WIDTH of central maximum mear DISTANCE between two MINIMUM
Width of central maximum `alpha=(2lambdaD)/(d)`
`:.` The new width obtained from modifying I and d,
`alpha.=((2lambda)(3D))/(((3)/(3)))`
`:.(alpha.)/(alpha)=4`
`:.` Four times


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