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In Fraunhoffer diffraction, the wavelength of light incident on the slit (d)/(2)where dis the width of the slit. What will be the number of bright fringes fromed on an infinitely extended screen placed at any distance from the slit ? |
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Answer» Solution :In Fraunhoffer diffraction condition for maximum is, `dsintheta=(2n+1)(lamda)/(2)""` where, N=1, 2, 3, …… but `lamda=(d)/(2)` is GIVEN. `:.dsintheta=(2n+1)(d)/(4)` `:.sintheta=((2n+1)/(4))` but `sinthetale1` `:.(2n+1)/(4)le1` `:.2n+1le4` `:.2nle3` `nle(3)/(2)` Thus, for integer value of n, its possible value =1, we have TWO first order maxima for n=1 and central maximum forn=0, so we have total three maxima. |
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