Saved Bookmarks
| 1. |
In given figure, let `DeltaU_(1)` and `DeltaU_(2)` be change in internal energy in process `ABC` and `CDA` respectively. `DeltaQ` and `W` be the net heta given and net work done by the system in the process `ABC +CDA`, then A. `DeltaU_(1) +DeltaU_(2) =0`B. `DeltaU_(1) - DeltaU_(2) =0`C. `DeltaQ - W = 0`D. `DeltaQ +W =0` |
| Answer» Correct Answer - A::C | |