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In given figure, sides QP and RQ to PQR are extended upto points S and T. If angle SPQ = 135 degree, angle PQR = 110 degree find angle PRQ |
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Answer» ∠PQT+∠PQR=180 ∘ (STRAIGHT angle made on LINE TR at point Q)110 ∘ +∠PQR=180 ∘ ∠PQR=180 ∘ −110 ∘ =70 ∘ In △PQR∠PSR=∠PQR+∠PRQ (Exterior angle of triangle is eqal to SUM of two interior angles)135 ∘ =70 ∘ +∠PRQ∠PRQ=135 ∘ −70 ∘ =65 |
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