1.

In gram panchayat election, three people were contesting election. 20% of the villagers did not come to vote. First Candidate got only 20% of the cast vote and second candidate got 30% of the remaining cast votes and the third candidate got rest of the votes. If candidate C got 1152 more votes than candidate A, find the total number of voters in the voting list?1. 35002. 45003. 20004. 4000

Answer» Correct Answer - Option 4 : 4000

Given:

% of uncast vote = 20%

Votes got by 1st Candidate = 20% of cast vote

Votes got by 2nd Candidate = 30% of the remaining vote

Votes got by 3rd Candidate = Total cast vote – (Votes of 1st Candidate + votes of 2nd Candidate)

Concept:

Consider the total votes to be 100x. Then proceed.

Calculation:

Let total number of voters be 100x

Cast vote = 80% of 100x = 80x

Vote received by A = 20% of 80x votes = 16x

Remaining votes = (80x – 16x) = 64x

Votes received by B = 30% of 64x votes = 19.2x votes

Remaining votes = (64x – 19.2x) = 44.8x votes

⇒ Votes received by 3rd candidate = 44.8x

Votes received by 3rd candidate – Votes received by 1st candidate = 1152

⇒ 44.8x – 16x = 1152

⇒ 28.8x = 1152

⇒ x = 40

Total number of voters in the voting list = 100x = 100 × 40 = 4000

∴ The total number of voters in the voting list is 4000.



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