1.

In H_(2) - O_(2) fuel cell the reaction occuring at cathode is

Answer»

`2 H_(2) + O_(2) to 2 H_(2) (L)`
`H^(+) + OH^(-) to H_(2)O`
`O_(2) + 2 H_(2)O + 4e^(-) to 4OH^(-)`
`H^(+) + E^(-) to (1//2) H_(2)`

Solution :In `H_(2) - O_(2)` FUEL cell , the reaction at cathode is `O_(2) + 2 H_(2)O + 4 e^(-) to 4 OH^(-)` .


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