In Haber process, 30 litres of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of the gaseous mixture under the aforesaid condition in the end?

In Haber process, 30 litres of dihydrogen and 30 litres of dinitrogen

1.	In Haber process, 30 litres of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of the gaseous mixture under the aforesaid condition in the end?
Answer» 20 litres `NH_3`, 25 litres `N_2`, 20 litres `H_2` 10 litres `NH_3`, 25 litres `N_2`, 15 litres `H_2` 20 litres `NH_3`, 10 litres `N_2`, 30 litres `H_2` 20 litres `NH_3`, 25 litres `N_2`, 15 litres `H_2` Solution :`N_(2)(g) + 3H_(2)(g) 1 L of `N_(2)` REACTS with 3 L of `H_(2)` to form 2 L of `NH_(3)`. Thus, `N_(2)` is the limiting reacant. 10 L `N_(2)` will react with 30 L `H_(2)` to form 20 L `NH_(3)`. As actual yield is 50% of the EXPECTED value, `NH_(3)` formed = 10 L, `N_(2)` reacted = 5L, `H_(2)` reacted = 15 L `THEREFORE` Mixture will contain 10 L `NH_(3), 25 L N_(2), 15 L H_(2)`