In how many ways 2 red pens, 3 blue pens and 4 black pens can be arranged if same color pens are indistinguishable?(a) 362880(b) 1260(c) 24(d) 105680This question was posed to me by my school teacher while I was bunking the class.The question is from Permutations-2 in division Permutations and Combinations of Mathematics – Class 11

In how many ways 2 red pens, 3 blue pens and 4 black pens can be arran

1.	In how many ways 2 red pens, 3 blue pens and 4 black pens can be arranged if same color pens are indistinguishable?(a) 362880(b) 1260(c) 24(d) 105680This question was posed to me by my school teacher while I was bunking the class.The question is from Permutations-2 in division Permutations and Combinations of Mathematics – Class 11
Answer» Correct answer is (B) 1260 To explain: Total NUMBER of pens are 2+3+4 = 9 out of which 2 are of 1 type, 3 are of 2^nd type and 4 are of 3^rd type so, total number of arrangements = \(\frac{9!}{2!3!4!} = \frac{98765}{2*6}\) = 1260.

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