1.

In hydrogen atom electron makes transist from n = 3 orbit to n = 2 orbit in time 1.2xx10^(-8) s. Then calculate the average torque (in Nm) that acts during this transition.

Answer»

`1.055xx10^(-26)`
`4.40xx10^(-27)`
`1.7xx10^(-26)`
`8.79xx10^(-27)`

Solution :`tau=(DeltaL)/(DELTAT)=(L_(2)-L_(1))/(Deltat)`
`((n_(2)h)/(2pi)-(n_(1)h)/(2pi))/(Deltat)=((n_(2)-n_(1))h)/(2piDeltat)`
`=((3-2)xx6.625xx10^(-34))/(2xx3.14xx1.2xx10^(-8))=8.79xx10^(-27)`


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