In hydrogen atom, energy of first excited state is –3.4 eV. Then fin – InterviewSolution

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1.	In hydrogen atom, energy of first excited state is –3.4 eV. Then find out K.E. of same orbit of hydrogen atom.
Answer» In hydrogen atom, energy of first excited state is $- 3.4 eV$ . Then find out K.E. of same orbit of hydrogen atom.

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