InterviewSolution
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InterviewSolution
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In hydrogen atom, the electron is making `6.6xx10^(15) rev//sec` around the nucleus in an orbit of radius `0.528 A`. The magnetic moment `(A-m^(2)) will beA. ` 1 xx 10^(-15)`B. `1 xx 10^(-10)`C. `1 xx 10^(-23)`D. `1 xx 10^(-27)` |
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Answer» Correct Answer - C Current , I `=6.6xx10^(15) xx 1.6xx10^(-19)` `=10.5xx10^(-4)A `. Area `A=piR^(2)=3.142 xx (0.528)^(2) xx 10^(-20) m^(2)` So, Magnetic moment `M=IA=10.5xx10^(-4) xx 3.142 xx (0.528)^(2) xx 10^(-20)` `= 10 xx 10^(-24)=10^(-23)` units |
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