1.

In hydrogen atom, the electron is moving round the nucleus with velocity 2.18 xx 10^(6) m//s is an orbit of radius of 0.528 Å. The acceleartion of the electron is

Answer»

`9 xx 10^(18)m//s^(2)`
`9 xx 10^(22)m//s^(2)`
`9 xx 10^(-22)m//s^(2)`
`9 xx 10^(-22)m//s^(2)`

Solution :The ELECTRON in a hydrogen ATOM, moves with CONSTANT acceleration, called CENTRIPETAL acceleration ROUND the nucleus. Acceleration of electron `a=v^(2)/r`
Given `v=2.18 xx 10^(6) m//s`,
`r=0.528 Å=0.528 xx 10^(-10)m`
`a=((2.18 xx 10^(6))^(2))/(0.528 xx 10^(-10))=9 xx 10^(22) m//s^(2)`


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