In hydrogen atom, when electron jumps from second to first orbit, then energy emitted is
Answer»
`-13.6 eV` `-27.2eV` `-6.8 eV` Noneof these
Solution :For hydrogen ATOM we know that `E_(1) = - 13.6 eV` and `E_(2) = -3.4 eV`. Hence, energy RADI ated for TRANSITION from n =2 to n = 1 state is `E= -3.4-(-13.6) - 10.2 eV`. Hence, option (d) is the correct answer.