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In hydrogon atom, electron excites from ground state to higher energy state and its orbital velocity is reduced to (1)/(3) rd of its initial value. The radius of the orbit in that higher energy state is : |
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Answer» R 9 `mvr=(nh)/(2pi)` `i.,e v PROP (1)/(r),(v_(1))/(v_(2))=(r_(2))/(v_(1))` `:. (v)/(v//z)=(r_(2))/(R) rArr r_(2)=3R`. |
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