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In lanthanides, Ce changes from +4 to +3 oxidation state.(a) True(b) FalseThis question was posed to me by my college director while I was bunking the class.The above asked question is from D and F-Block Elements in division D and F-Block Elements of Chemistry – Class 12

Answer»

Correct option is (a) True

Easy explanation: In lanthanides, Ce changes from +4 to +3 oxidation state. Formation of Ce^4+ is favorable DUE to its NOBLE GAS configuration. HOWEVER, Ce^+4 changes to Ce^+3 as it is a strong oxidizing agent. The E° value of Ce^+4/Ce^+3 is +1.74 V.



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