1.

In lead accumulator the electrolyte used is

Answer»

`10% H_(2)SO_(4)` with specific GRAVITY 2.15
38%` H_(2)SO_(4)` with specific gravity 1.28
10% `H_(2)SO_(4)` with specific gravity 2.215
38% `H_(2)SO_(4)` with specific gravity 2.15

Solution :38% `H_(2)SO_(4)` with 1.2 g/ML DENSITY is USED in lead accumulator.
`M=(W)/(m)xx(1000)/(100xxd)=(38)/(98)xx(1000)/(100xx1.2)=3.2 M`


Discussion

No Comment Found

Related InterviewSolutions